Hi Ashok,
-----原始邮件-----
发件人: "ashok jallepalli" <ash.nani@gmail.com>
发送时间: 2017年3月27日 星期一
收件人: "Jian Yu" <yuj@buaa.edu.cn>
抄送: nektar-users <nektar-users@imperial.ac.uk>
主题: [SPAM] Re: [Nektar-users] On the C0ProjectionHi Jain,"If I have a discontinuous(across element interface) distribution of var, then what has been done during the above procedure?"- You have projected your variable/field on CG Field. i.e. introduced C0 continuity across boundaries of the element.- You projected your field on a field which has C0 continuity at element boundaries.Example:-Let us assume your var is a piece-wise p1(eg:3) degree polynomial. Exactly dis-continuous at element boundaries.- Let us assume you are projecting your var on a field of p1.- if you would have used MultiRegions::DisContField2D. The two operations would not have affected your variable. .i.e. var = var_smooth, var_smooth is C^{-1}(dis-cont) at element boundaries and p1 polynomial inside each element. - Since you have used MultiRegions::ContField2D, Your var_Smooth has C0 continuity and you have p1 polynomial inside each element, but var != var_smooth. (Since you have reduced the degree of freedom).The best section to read in the book would be section 2.2 from page 21.Ashok.On Sun, Mar 26, 2017 at 2:02 PM, Jian Yu <yuj@buaa.edu.cn> wrote:Dear everyone,
I am trying to figure out the specific formulation when performing C0Projection, i.e.
If I define m_c0ProjectExp as following
m_c0ProjectExp = MemoryManager<MultiRegions::ContField2D>:: AllocateSharedPtr(m_session,m_ graph,"DefaultVar");
Then what is the specific algorithm when perform the following command(all relative options are default)?
m_c0ProjectExp->FwdTrans(var,var_Coeffs);
m_c0ProjectExp->BwdTrans(var_Coeffs,var_smooth);
If I have a discontinuous(across element interface) distribution of var, then what has been done during the above procedure?
Could anyone please recommend me some materials on this? If possible, where can I find this topic on the book "Spectral/hp Element Methods for Computational Fluid Dynamics"
Thank you in advance!
Best wishes,
Jian Yu
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