If you are using the flow rate option then the pressure is decomposed into a component supporting the mass flow rate (which for Poiseuille flow is a linearly varying function ) plus the perturbation. So it is the ’true’ pressure if you add back in the linearly varying component associated with the mass flow rate component.

On 10 Oct 2019, at 20:16, Adriano Takata <atakata@uwo.ca> wrote:

Hi, how are you?

(Nektar++ 5.0)

I am working in Poiseuille flow 2D with periodic boundary conditions.

I get the solutions (u = (1 + y) * (1-y), v = 0, and p = 0) with the solver.

The pressure is 0 due to the flowrateforce, but I would like to know if I can get the "true" pressure thought the velocity field.

Thank you.

Adriano Sueke Takata

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