That is what is am doing and it still complains about Mismatching Function Spaces.. So what I have now is, let's say

u1_ = Function(V)
u2_ = Function(V)
w = Function(W), where W = V*V
v = TestFunction(W)

u1, u2 = split(w)
v1, v2 = split(v)                Here I also tried defining instead v1, v2 = TestFunctions(W).

F =  fn(u1, u2, u1_, u2_; v1)
G = fn(u1, u2, u1_, u2_; v2)

u1, u2 = w.split()            OR does this need to be after the variational problem is solved?
                                        I tried both with the same outcome.

solve(F == 0, w)

u1_.assign(u1)
u2_.assign(u2).




On 26/11/14 12:45, Lawrence Mitchell wrote:
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On 26/11/14 12:24, Anna Kalogirou wrote:
Do I still need to define u1, u2, u3 = Functions(V), where V is in 
original space? After the variational problem is solved I split w
as

u1, u2, u3 = split(w)

and try to print u1, u2, u3 in files, but I get

AttributeError: 'Indexed' object has no attribute
'function_space'.
Aha, you run into the split(w) vs. w.split() problem.

When you're defining your variational form, you need to use the
former.  For output purposes (and assignment in a timestepping loop)
you need to use the latter.

e.g.

u1, u2 = split(w)

F = fn(u1, u2; v)

u1, u2 = w.split()

solve(F == 0, w)

u1_.assign(u1)
u2_.assign(u2)

etc...

Also, I can't interpolate or assign. In the end, I want to pass u1,
u2, u3 to some other functions u1_, u2_, u3_, which also appear in
the residual expressions. But this produces a 'Mismatching function
spaces' error.
I hope the above should also clear up this problem.

Cheers,

Lawrence
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 Dr Anna Kalogirou
 Research Fellow
 School of Mathematics
 University of Leeds