chemistry problem...

a small chemistry problem! I'd like to know why catalytic reforming raises the octane number by creating branched isomers. The real question is why does a branched isomer burn more slowly than the straight chain version. Would anyone know? Many thanks, keith wilkinson ----- chemweb: A list for Chemical Applications of the Internet. Archived as: http://www.ch.ic.ac.uk/hypermail/chemweb/ To unsubscribe, send to listserver@ic.ac.uk the following message; unsubscribe chemweb List coordinator, Henry Rzepa (rzepa@ic.ac.uk)